Question:

What's the derivative of sin(6x)^3/4?

by Guest32180  |  earlier

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What's the derivative of sin(6x)^3/4?

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  1. LOL...two different answers...monu is the correct one


  2. (sin6x)^3/4

    = 3/4 * (sin6x)^-1/4 * cos 6x * 6

    = 9/2 * cos6x * (sin 6x)-^1/4

    = 9 cos 6x

      ---------------

       2 (sin6x)^1/4

    Hope it may help you.

    Thank you.

  3. 18/4 * (sin(6x)^(-1/4)) * cos(6x)

  4.   dy/dx  =  (3/4) * (sin6x)^(-1/4) * (cos6x)*6

              

                 =  (9/2) * (sin6x)^(-1/4) * (cos6x)
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