What's the output of the following program and why? ?

Question

int main()

{

float a = 12.5;

printf("%d\n", a);

printf("%d\n", *(int *)&a);

return 0;

}

Answer 1

Hi there.

The output will be zero as you have assigned float value but are using %d at the place of %f .

output will look like:

0

0

I think I answered it .

Good Luck.

Answer 2

I think the answer will be like this:

12

12

Because as far as I know, when you use %d for a float or double number, it automatically round it off.

Good luck