the problem is: The current in am inductor is changing at the rate of 100A/s, and the inductor emf is 40V. What is its self-inductance?
Here is how i did it: i used faraday's law, which states: E=-L di/dt
since we know E=40v and di/dt=100A/s here, i just plugged in, and got L=.4H, but the strange thing is the answer for this problem should be 14.6mT.
First, shouldnt the unit for L being H? i thought mT is the unit for magnetic field.
Second, how to get the answer 14.6?
Anyone got an idea for this?
Thanks
Tags: