Question:

What are the answers to these math problem?

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1) (3x^2y^4)^2

2) 4x^6y^9

-------------------

8x^2y

3) (4x^3y^2)(2xy^8)

4) 2x+ 3y= 11

y= -2x+1

5) 5x +2y=10

12x-8y=24

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1 ANSWERS


  1. 1) (3x^2y^4)^2 = 3²(x²)²(y^4)² = 9x^4y^8

    2) 4x^6y^9

    ------------------- = (x^4y^8) / 2

    8x^2y

    3) (4x^3y^2)(2xy^8) = 4*2x^(3+1)y^(2+8) = 8x^4y^(10)

    4) 2x+ 3y= 11

    y= -2x+1

    2x + 3(-2x+1) = 11

    2x - 6x + 3 = 11

    -4x = 8

    x = -2

    y = -2(-2) + 1

    y = 4 + 1

    y = 5

    5) 5x +2y=10

    12x-8y=24

    Multiply the first equation by 4 and add it to the second equation.

    4(5x + 2y = 10)

    20x + 8y = 40

    + (12x - 8y = 24)

    ---------------------

    32x = 64

    x = 2

    Substitute this into the first equation and solve for y

    5x + 2y = 10

    5*2 + 2y = 10

    10 + 2y = 10

    2y = 0

    y = 0

    Hope this helps you!

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