Question:

What are the chances of dying in Russian Roulette if there are two six shooters?

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I was in a piano lesson when I thought of this.

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  1. The same as your opponent, 50/50. It doesn't matter how many guns or bullets, same odds of loosing.


  2. depends on how many chambers the gun has, how many bullets, and how many rounds have been fired blank before your up lol....still the odds in that game are never good haha

  3. So you're pointing both guns to your head and pulling the trigger on both and there's a bullet in each gun.  So yeah that's 1 in 3.

    King Cobra Poker

  4. 1:6

  5. I'm not sure what you mean by your question.  Do you mean two chambers with bullets and one gun?  Or two guns each with a bullet in one chamber?

    But if you mean one gun and two bullets, you'd have a one in three chance of dying.  Assuming the shot is fatal of course.

    Your odds would also depend on if the gun was randomized each time you played.

    By the time you each had two turns, there would be a very good chance that one of you would be dead.

    In any case, who cares?  Only a suicidal maniac would play anyway.

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