What are the final velocities of two balls in a perfectly elastic collision?

Question

Ball 1, with a mass of 80 g and traveling at 14 m/s, collides head on with ball 2, which has a mass of 280 g and is initially at rest.

What are the final velocities of each ball if the collision is perfectly elastic?

Answer 1

Oh wise guy eh? Try to get me all excited over physics and the velocity of flying balls?  But you certainly have my attention my dear.  Wow 14 m/s?  miles per second? No way? really?

Holy makarena. That must really hurt even if the boys can't run that fast. ow ow ow.

Answer 2

cookie

Answer 3

vf1=(m1-m2/m1+m2)*vi1+(2*m2/m1+m2)*vi2

and for vf2

vf2=(2*m1/m1+m2)*vi1-(m1-m2*vi2)/m1+m2



here vi1=intial velocity of ball 1

         vi2=intial velocity of ball 2

         m1=mass of first ball

         m2=mass of second ball

in ur case v1=14m/s

                  v2=0

                  m1=.080 kg

                  m2=.28 kg

remember to convert mass into kg  

        

put the values and get the answer

Answer 4

For perfectly elastic collisions, remember you need to conserve two things:

1) Conserve the linear momentum

2) conserve the kinetic energy of the two balls.

use the equations for these and solve them to get whatever you have unknown.

Answer 5

oh child they are bowling up  in its

alley,*

you use 3  FINGERS THAT'S ALL

the thumb the index and its solo,

finger * its french * [the um bats so *] since when women know math -Amati's * they love chocolate *

and child if they gave you a whole BOX *

DO NOT COUNT *

BITE EVERY ONE OF THEM *

  so fat CHANCE *[keep what you got

in the bank [C NOTES *

YOU PAY THEM TO COUNT *

GUESS WHAT *

[you become Thar administrator  

Girl  bank thy notes *

peace *thy monkey * [ape thy amazing savings [x-mess *

love your childs *

[i wanna go home *]  

off i go  to put some lip stick *

[psst this is a game  not your life *

if they were they would not be here *

in fact they are at work *

and you are at your  lea-sure ,*08 goal *

  HA RETIRED ,,*

Answer 6

In perfectly elastic collision, no energy escapes out.

P= mv = 80/1000*14= 1.12 kg m/s

after head on collision , the balls would attach together & move with same velocity(no friction).

By conservation of momentum,

p=(m1+m2)v

v=1.12/(80/1000 +280/1000)= 3.1m/s