What are the five typical elements that lose electrons the easiest?

Question

What are the five typical elements that lose electrons the easiest?

Answer 1

dunno

Answer 2

The best way to gauge how likely an element will lose an electron is through the element's ionization energy, which is the energy required to remove electrons from the atom.

The five element's with the lowest first ionization energies (meaning the energy required to remove one electron from the neutral atom) are as follows [1]:

1. Cesium: 375.7 kJ/mol

2. Francium: 380 kJ/mol

3. Rubidium: 403 kJ/mol

4. Potassium: 418.8 kJ/mol

5. Lawrencium: 470 kJ/mol

So those are the five most likely elements to lose a single electron to form an cation with a +1 charge.

If you wanted to know which are the most likely to lose more than one electron, simply check my source and look at the combined energies required to remove the number of electrons you desire.

Answer 3

Group 1 elements (first column), not including H

Na, K, etc

Answer 4

Group 15 which have oxidation numbers of -3: nitrogen, phosphorus, arsenic, antimony and bismuth

Answer 5

the alkali metals.