What are the products for NH4+NaOH --> ???

Question

What are the products for this reaction

Answer 1

first of all, NH4+ is a positive ion , it must has its negative ion

please write the complete formula first

Answer 2

NH4+(aq) + NaOH(aq) ------> Na+(aq) + NH3(aq) + H2O(l)

Interestingly enough, there is such a thing as "ammonium metal", which is neutral NH4. But it is unstable and exists only as an amalgam.

Edit: Another thumbs down? What's going on here? Who doesn't like my answers?

Answer 3

But I  think that in this case we're talking about the ammonium ion, NH4+, and whoever wrote the question omitted the anion.

Ammonium ion can behave as an acid and donate a proton to the hydroxide ion of the base to make water.

NH4+  +   OH- <==>  NH3(aq) + HOH(l)

We write this as an equilibrium because ammonia is itself a base compared to water.  NH3 can accept a proton from water to make ammonium ion and hydroxide ion.

Depending on whether the NaOH is solid or in solution, the Na may or may not be included in the ionic equation.  If the NaOH is in solution, the sodium ion is also a spectator ion.

If the sodium hydroxide happens to be in the solid state, then the ionic equation will look like this:

NH4+  +  NaOH(s)  -->  Na+  +  NH3(aq) + HOH(l)