What are the roots of a generic quadratic equation? A*x^2 + B*x + C= 0?

Question

What are the roots of a generic quadratic equation? A*x^2 + B*x + C= 0?

Answer 1

You can derive the quadratic formula from completing the square:

x =( -B +/- sqrt(B^2 -4AC) ) / 2A

Answer 2

ax^2+bx+c=0

ax^2+bx=-c

x^2+(b/a)x=(-c/a)

x^2+(b/a)x+((b^2)/(4a^2))=(b^2-4ac)/(4...

(x+((b)/(2a)))^2=(b^2-4ac)/(4a^2)

x+((b)/(2a))=(sqrt(b^2-4ac))/(2a) OR x+((b)/(2a))=(-sqrt(b^2-4ac))/(2a)

x=(-b+sqrt((b^2)-4ac))/(2a) OR x=(-b-sqrt((b^2)-4ac))/(2a)

Answer 3

x = [-b +- sqrt (b^2 - 4ac)]/2a

Answer 4

You will be able to find the Roots or Zeros of a generic quadratic equation by using the following formula: X = (-b ± √b^2 – 4ac) ÷ 2a