What current is required to electroplate 6.07 ug of gold in 30 min from a gold (III) chloride aqueous solution

Question

What current is required to electroplate 6.07 ug of gold in 30 min from a gold (III) chloride aqueous solution

Answer 1

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Answer 2

6.07 ug = 6.07 x 10^-6 g

Moles Gold = 6.07 x 10^-6 g/ 197 g/mol =3.1 x 10^-8

Au3+ + 3e- >> Au

Fot every 3 Faradays consumed 1 mole of Au is produced

3.1 x 10^-8 x 3 =9.2 x 10^-8 F

96500 C/F x 9.2 x 10^-8 =0.00892 Coulomb

30 min = 1800 seconds

0.00892 C / 1800 = 4.96 x 10^-6 Ampere => 0.00496 mA