What do I do with this algebra equation (x in the parentheses) ?

Question

I have the following equation for my algebra homework (solving for x):

7-(5-x) = x+3, and then I simplified it to -3+7-(5-x)=x. Can I just add the x to the other side of the equation, regardless of whether or not it's in parentheses, or must I do something special to it because it's in parentheses?

Answer 1

Ummm i dont rely no how to answer your question so il say it based on how i would answer this question. First solve what is in the brackets.

The equation would than become: -35-7x=x+3

Now put all the whole numbers on one side of the equation and put the numbers with a variable (which is x) on another side.

When you move a number from one side to another side of an equation is changes from posotive to negatve or negative to posotive.

So the equation will now look like this:-7x-x=3+35

-8x=38

Since the equation is reduced, do cross multiplication, the -8x goes below 38 making it a fraction.x= -38/8

Divide the number and denominator by 2 making the fraction

x= - 19/4 or make it 4 and 3 fourth.

Therefore x equals -19/4.

Answer 2

7-(5-x) = x+3

multiply the - to parentheses

7-5+x = x + 3

you get 2+x=x-3

x is undefined

or

7-(5-x) = X+3

-(5-x) = X +3 -7

-(5-x)=X-4

(5-x)=-x+4

5-x=-x+4

answer is still undefine

Answer 3

you distribute the negative sign to everything in parentheses:

7-(5-x) = x+3

7-5+x = x+3

now simplify and isolate x:

2+x=x+3

answer comes out to be no solution