What if the distance around a tennis court is 228feet?

Question

If the length of the court is 6 feet more than twice the width what would the dimensions be. Please these four steps:

1.How you understood the problem.

2. How you devised out the plan.

3. How you carried out the plan.

4. Looking back at the problem.

Answer 1

draw the court first

you know that length = 2width + 6

distance around the court = perimeter = 2 (length + width)

= 2(width + 2width + 6)=2 (3 width + 6) = 6 width + 12 = 228

therefore 6 width = 216 and 1 width = 36 feet

if width = 36, length = 2*36+ 6 = 78 feet

looking back add up the four sides = 36+78+36+78 = 228.  this matches the info received

problem solved!!

AM

Answer 2

Length = 2 x  width + 6 feet

If w = width

and the perimeter of a rectangle is = to twice its length and twice its width added together

228 = 2(2w + 6) + 2w

228 = 4w + 12 + 2w

228 - 12 = 6w

216 = 6w

216/6 = w

w = 36

To check if this correct

36 + 36 + 72 + 72 + 12 should = 228

and it does.