What is a counter example for ...

Question

the square root of a number x is always less than x?

Please explain too, I'm lost.

Answer 1

The square root is a number that when multiplied times itself is the square-number.  Such as 8x8=64.  8 times itself is 64.  8 is less than 64.  64 is greater than 8.  The end result would be the same if you multiplied -8 times -8 because -8x-8=64.

However, 0 x 0 = 0, and 1 x 1 = 1.  In these cases, the product is *equal to* not greater than the multiplier/multiplicand.  And the number to be squared is equal to not less than the product.