What is a decent health insurance company can I purchase?

Question

I am unemployed and need health insurance so i wont have to pay $200 per doctor's visit,plus the full amount for medicine.Open for all suggestions.

Thank you for your help!

Answer 1

If you want specific companies and suggestions, you need to provide a lot more information.  You didn't even tell us where you live.   A company that offers very good insurance at a good rate where I live might not even write where you are.

It isn't likely that you will find a carrier that will write a plan for you that will cost less than doctor visits and medicines.  They are taking on so much more responsibility for your health that the premium will more than likely be more than your current out of pocket expenses for doctors and medicine.

Answer 2

Talk to an insurance broker that handles individual health policies.  Beware of "internet" offers.

Answer 3

Hi GVictoria

Have you tried talking to a local agent in your area?  This is usually a good approach because they will know the insurance companies and their plans well.  They should be a great resource for you in your search.

If you want to connect with an agent in your area, complete the form below and one will call you and help get you started.  Good luck!

http://www.insureme.com/landing.aspx?Ref...

Jared Balis

http://www.utahinsurance.org

Answer 4

The fact that you are already taking medications indicate that you have a pre-existing health condition. Depending upon the this unspecified health condition you may not be able to qualify for insurance through a private commercial carrier. They may not write the insurance at all or they may write the insurance but exclude coverage for your health condition.

In many States Blue Cross Blue Shield will accept you without regard to your health status.

Check with an agent. He/she know the markets available in your State and can propose plans that take into account your health status and your limited budget (but be prepared health insurance is not inexpensive).