What is an equation of the line perpendicular to -2-5y=10?

Question

No stupid/silly answers. Please spare me.

Answer 1

The line you're giving us is a horizontal line:

y= - 12/5

A perpendicular would be of the form x= a constant (a vertical line).

Answer 2

2-5y=10?

2-10 = 5y

-8 = 5y

-8/5 = y

so u should know by now that if there are no xs in the equation , just ys that this is a horixontal line thorugh -8/5

so any line is perpendicular to this if x= any number, i.e the equation of a line that is vertical.  i.e x = +2

But if u really meant to type 2x-5y=10

then -5y = -2x +10

y = 2x/5 -2

and the slope of a line perpendicular to this is -5/2

so y = -5x/2 +b

Answer 3

Simplified, y = -8/5

a perpendicular line would be x = c

where c is a constant of any real number.