What is being oxidized, what is being reduced in this reaction

Question

2 N2H4 (g) N2O4(g) -----> N2 (g) 4 H2O (g)

Answer 1

left side is being oxidized and the right side is being reduced, or broken down

Answer 2

Nitrogen is being reduced (Oxidation number is 4+ in N2O4 and then goes down to 0 in N2)

Nitrogen is also being oxidized (Oxidation number is 2- in N2H4 and then goes up to 0 in N2)

Hope this helps :)

Answer 3

Hydrogen is being oxidized and sodiumhidrie is being reduced