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What is pK for a REDOX reaction under standard conditions if n = 5 and E° = 0.309v??CAN ANYONE HELP ME!!!!?

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What is pK for a REDOX reaction under standard conditions if n = 5 and E° = 0.309v?

CAN ANYONE HELP ME PLZ!!!

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  1. Nernst equation:

    E = Eo - 0.0592/n (logQ)

    becomes @ equilibrium:

    0 = Eo - 0.0592/n(logK)

    so:

    Eo = 0.0592/n log K

    0.309 = 0.0592 / 5 (logK)

    log K = 26.098

    10^x gives

    K = 1.25e26

    your answer: pK = -26.098

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