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What is the [OH-] for a solution at 25 degrees C that has a ph= 4.29? A. 1.4 x 10^-2 B. 1.9 x 10^-10?

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What is the [OH-] for a solution at 25 degrees C that has a ph= 4.29? A. 1.4 x 10^-2 B. 1.9 x 10^-10?

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  1. pOH = 14 - pH = 14.0 - 4.29 = 9.7

    [OH-] = 10^-pOH = 10^-9.7

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