Question:

What is the acceleration of a rocketship that has a mass of?

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6.1*10 6 and has a thrust of 48.1*10 8 N?

HELP!!!

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  1. mass=6,100,000 kg

    Force=4,810,000,000 Newtons

    a=F/m

    a=(4,810,000,000)/6,100,000)

    a=788.52 m/s^2


  2. acceleratiin = 788.525 m/s2

  3. mass =  = 6.1x10^6 kg (you didn't specify units so I am assuming you mean kg)

    thrust = 48.1x10^8 N

    The old formula: F = ma

    48.1x10^8  = 6.1x10^6a

    7.885x10^2 m/s^2 = a

    The acceleration is 788.5 m/s^2. A rather large acceleration

  4. F = dm/dt v + m dv/dt; where dm/dt is the loss of mass over time (e.g., due to burning fuel), m is total mass including fuel, and dv/dt = a the acceleration of the mass.  F is the net force acting on the ship, in this case the thrust 48.1E8 N.  As you failed to give the burn rate of the fuel, whatever answer you get will be incorrect.  You also failed to give the mass units; so I'll presume kg.

    If you can somehow get thrust without buring fuel, so that dm/dt = 0, you would have F = m dv/dt = ma = 48.1E8 = 6.1E6 a and a = 48.1E8/6.1E6 ~ 8E2 or 800 m/sec^2 acceleration.  That's more than 80 times the acceleration due to gravity...more than 80 g's.  Who- or whatever is in that ship will be smashed like a bug on a windshield.  Your passenger does in fact need HELP.

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