What is the answer for (x-6)(x+5)?

Question

i have a problem getting the answer

Answer 1

First you multiply out the factors:

If (x-6)(x+5)=0

then (x^2)-6x+5x-(6*5) = (x^2)-x-30 = 0

Then, plugging the terms a=1, b=-1, c=-30 into the quadratic root equation:

x = {(--1) +/- SQRT(1 - 4*1*-30)} / (2*1)

= 0,5*(1 +/- SQRT(121))

= half of (1+11) or half of (1-11)

Therefore, x=6 or x=-5

In general, the solutions to the quadratic equation y=ax^2+bx+c=0 are:

x= minus b plus or minus the square root of {b-squared minus 4ac}, all over 2a;

see reference.

___________

There is of course a quicker and more attractive way to get to the answer.

If (x-6)(x+5)=0, then, when y=0, x-6=0 and x+5=0, because 0=0*0;

therefore x=6 or x=-5 when y=0.

By the way, this is a language - the universal language of algebra.

Answer 2

The easiest way is...

x(x+5) - 6(x+5)

= x² + 5x -6x -30

= x² - x - 30

Answer 3

x ² -x-30

Answer 4

(x-6)(x+5)= x^2 - x - 30

Answer 5

edit.

(x-6)(x+5)

x2 + 5x

    - 6x - 30

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X2 - x - 30

Answer Mine.?

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