What is the answer to 7a-5+7-5a?

Question

Also, what is 8b+3y+4b-5y?

Answer 1

7a-5+7-5a=2a+2=2(a+1)

8b+3y+4b-5y=12b-2y

Answer 2

1)

7a - 5 + 7 - 5a

= 7a - 5a - 5 + 7

= 2a + 2

= 2(a + 2)

2)

8b + 3y + 4b - 5y

= 8b + 4b + 3y - 5y

= 12b - 2y

= 2(6b - y)

Answer 3

7a -5+7-5a= 2a+2

8b+3y+4b-5y= 12b-2y

Answer 4

7a-5+7-5a=2a+2

8b+3y+4b-5y=12b-2y

Answer 5

you can't add apples and oranges or unlike variables. so the key is to group together your like terms (variables) 7a-5a=2a   -5+7= 2 so the answer is 2a+2 the same goes for the next problem group the b's and the y's make sure you take notice of their sign and you can get the answer just by looking at it 12b-2y. good luck

Answer 6

a = -1

b = y/6

If both of them are equal to zero, that is:

first:  7a-5+7-5a = 0;  2a = -2;  a=-1

second: 8b+3y+4b-5y = 0; 12b = 2y; y = 6b

Answer 7

2a+2

12b-2y

Answer 8

2a+2   and 12b-2y add the numbers (coefficients) that correspond to the same letters (variables)

Answer 9

Either you're lazy or you don't understand, so I may as well explain:

When you deal with adding or substracting pronumerals, you have to group similar terms together.

7a-5+7-5a

7a-5a-5+7

=2a+2 (You can only minus the a's together and the numbers without pronumerals together)

Answer 10

7a-5+7-5a

(7a-5a)+(7-5)

a(7-5)+(7-5)

a(2)+(2)

2a+2     You could leave it like this

2(a+1)     Or like this

8b+3y+4b-5y

(8b+4b)+(3y-5y)

b(8+4)+y(3-5)

12b-2y

12k+7=10k-9

12k-10k=-9-7

2k=-16

k=-8

3q+10=2q+18

3q-2q=18-10

q=8

Answer 11

combine like terms and you get answer for the first one. Same with second.

Answer 1: 2a+2

Now try the second one. ;) You can learn unless you try

Answer 12

7a-5+7-5a

= 2a - 2

8b+3y+4b-5y

= 12b - 2y

Answer 13

42!

Answer 14

First what you do is group the like terms together by re-arranging the order of the equation. so for the first one you asked you would change: 7a-5+7-5a to 7a-5a-5+7

then what you do is 7a - 5a = 2a

and

-5 + 7 = +2

so 2a + 2

for the second one you asked you do the same thing:

8b + 3y + 4b - 5y becomes 8b + 4b +3y - 5y = 12b - 2y

for the third one simplify like so:

3(a-4)=7a-10

open paranthesis by multiplying everything inside by 3

3a - 12 = 7a - 10

add 10 to both sides

3a - 2 = 7a

subtract 3a from both sides

- 2 = 4a

divide both sides by four

a = -0.5

for the part with the pronumerals, same as above, simplify:

12k+7=10k-9

subtract 7 from both sides

12k = 10k - 16

subtract 10k from both sides

2k = -16

divide both sides by two

k = -8

3q+10=2q+18

subtract 10

3q = 2q + 8

subtract 2q

q = 8

Answer 15

Rearrange it as  7a-5a+7-5=2a+2

                       8b+4b+3y-5y=12b-2y

Answer 16

7a-5+7-5a

Group like terms (all the a's and all the lone numerals together)

=7a-5a-5+7

=2a+2

8b+3y+4b-5y

Again, group like terms (all the b's and all the y's together)

=8b+4b+3y-5y

=12b-2y

3(a-4)=7a-10

3a-12=7a-10 [Expanding bracket on left-hand-side]

7a-3a=-12+10 [Moving all the a's to the same side of the equation]

4a=-2 [Simplifying]

a= -1/2 or -0.5