What is the area of a regular hexagon whose sides are each 12 inches long?

Question

Round to the nearest square inch.

Answer 1

Connect the six vertices of a regular hexagon to its center, creating 6 equilateral triangles.  Thus the area of a regular hexagon, whose sides have length 1, is 3×sqrt(3)/2.  If each side has length s, the area is multiplied by s^2.
Area = [s^2*3*sqrt(3)]/2 = 12^2*3*sqrt(3)/2 = 374 square inches

Answer 2

Connect the six vertices of a regular hexagon to its center, creating 6 equilateral triangles.  Thus the area of a regular hexagon, whose sides have length 1, is 3×sqrt(3)/2.  If each side has length s, the area is multiplied by s^2.
Area = [s^2*3*sqrt(3)]/2 = 12^2*3*sqrt(3)/2 = 374 square inches

Answer 3

Connect the six vertices of a regular hexagon to its center, creating 6 equilateral triangles.  Thus the area of a regular hexagon, whose sides have length 1, is 3×sqrt(3)/2.  If each side has length s, the area is multiplied by s^2.
Area = [s^2*3*sqrt(3)]/2 = 12^2*3*sqrt(3)/2 = 374 square inches