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What is the area of y=sin2x using integral calculus. the answer in the calculator is 57, if manually it's 1.?

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help me please, I don't know what's the real answer. it's the area of one arch only.

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  1. π/2

    . ∫sin(2x) dx= -[cos(2x)]/2 [x=0 to π/2]=-(cosπ-cos0)/2=1

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