What is the asymptote of the graph y=sec(8x)?

Question

What is the asymptote of the graph y=sec(8x)?

Answer 1

For y = sec(x) there are asympotes at 90 and 270

so there should be at 90/8 and 270/8 for sec(8x)

Answer 2

y = sec(8x) is the same as y = 1 / cos(8x), so the function will be undefined when cos(8x) = 0. cos(x) is zero at π/2 and 3π/2. That means this function is 1/8 lower or π/16, 3π/16 and every π/8 point until 15π/16.