What is the base-10 logarithm of the molar solubility of this compound when pH = 11.664???CAN ANYONE HELP ME!!

Question

For ferrous hydroxide, pKsp = 15.097. What is the base-10 logarithm of the molar solubility of this compound when pH = 11.664?

Can ANYONE HELP ME WITH THIS PROBLEM!!!?!?

Answer 1

Fe(OH)3 <------> Fe3+ + 3 OH-

Ksp = 10^-15.097 = 7.998 x 10^-16

pOH = 14 - 11.664 =2.336

[OH-] = 10^-2.336 =0.00461 M

[Fe3+] = 7.998 x 10^-16 / (0.00461)^3 =8 x 10^-9 M