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What is the change in oxidation number of this reaction? CHEM?

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What is the change in oxidation number of the reduced species in the reaction shown below?

3Cu + 2NO3- + 8H+ → 2NO + 4H2O + 3Cu2+

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  1. N is reduced in the reaction, going from an oxidation number of +5 in NO31- to +2 in NO, which represents a gain of 3e- per N.

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