What is the change in oxidation state of Cr

Question

in the half rxn: Cr2O7 ^2- -> Cr^3

Note that oxygen retains an oxidation state of -2

Answer 1

Cr2O7^2-

2 x Cr + 7 x 2- = 2-

2Cr = 2- - 14

Cr=6+

Conclution= 6+ to 3+

Answer 2

Goes from Cr^6+ to Cr^3+

Answer 3

IT.S +6 TO +3 FOR THE OXIDATION STATE

6+ AND 3+ WOULD BE FOR THE ELECTRICAL CHARGE,BUT IT.S NOT THE CASE