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What is the concentration of CN- ion in a 0.400 molar solution of K4Fe(CN)6?

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Kd for (Fe(CN)6)4- is 1.3 x 10^ -37

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  1. there are 6 CN- anions and have you have the molarity of the molecule so just multiply 6 x .4 = 2.4 M of CN-

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