Question:

What is the discharge of an 8 inches pipe 130 meters above sea level to a tank 30 meters above sea level.?

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What is the discharge of an 8 inches pipe 130 meters above sea level to a tank 30 meters above sea level.?

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  1. Q = cAV

    Where:

    Q = rate of discharge

    c = Coefficient of discharge

    A = are of the pipe

    V =velocity of discharge

    Assuming that he coefficient of discharge for a circular pipe is c =0.8;

    V = sqrt (2gh)

    h = (130 -30) 3.28 = 328 ft.

    = 32ft/s^2

    V = 102.45 ft/sec

    A = (pi(8^2)/4)/144 = 0.3491 sq.ft

    Q = 0.8 x 102.45 x 0.3491 = 28.609 cu ft/sec


  2. Draco 4843 is correct if you ignore the friction in the pipe, but at 102ft/sec this will be considerable.

    I think that the formula to use is

    H = 16 x friction coeff x L Q^2 / (2gPI^2D^5)

    H = 100m

    Friction coeff (lambda) = 0.2

    L = say 200m

    D = 0.2m

    so Q = (H x 2 xg x PI^2 x D^5/(16 x 0.02 x 200))^0.5

    Q = 0.44m3/sec

    V = 14m/sec

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