What is the domain of g(t) = sin (e^-t)? ?

Question

The graph is very weird in the first place... I thought the answer is -infinity < t < infinity (because a sine of any angle is possible), but that doesn't seem to be the answer. And I dunno whether e^-t is in radians or degrees. I guess radians... but either way, how do you find the domain of this function? My friend asked me this question... Please help!

Answer 1

The domain for the sine function is -infinity &lt; t &lt; infinity (because a sine of any angle is possible). You are correct.

e^-t is in radians (that&#039;s what I think).

If you know t, you can find e^-t.

The domain of a functions is all values for which the function has a meaningful value.

consider f(x) = 1/(x-1) . Any x will do, but not 1, because when x=1, f(x) is undefined.

sin(x) can be defined for any number (in degrees or radians).