Question:

What is the dy/dx for y=a^3?

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answer is 0 but i need to know how to get it

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  1. its 0 only if a is a constant


  2. dy/da=(3a^2)

  3. It is a rule that the d(constant)=0

    Assuming a is not a constant the answer would be

    dy/dx=(3a^2) d(a)/dx

    if a = constant number then d(constant)/dx=0 therefore dy/dx=0

    since 3a^2*0 = 0


  4. the answer is 0 because you are supposed to find out the derivative of a constant ( y=a^3) and derivative of a constt. number is 0..

  5. Simple. Differentiation of any constant is always zero. Since a is constant, a^3 is also constant and hence dy/dx=0.

  6. constant OR exponential function

    well for the dy/dx to be zero then the function must be constant which means that a is a constant

    or it could also mean that a is an e, that is that its an exponential function which means really that it has no gradient so teh dy/dx is also zero

  7. Differentiation of any constant value is 0 and a^3 is a constant.

  8. It should be zero.Because you are integrating y against x.

    But, if the question is dy/da ; y=a^3 then dy=3a^2 da.

    Or dy/dx ; y=x^3 then dy=3x^2 dx.

  9. there is no term of x in y, so y is basically constant. and as it is constant it does not change in terms of x. derivative is the rate of change of y with respect to x which is zero in this case

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