Question:

What is the force of the electric field on a proton if the field is set up between the plates of a discharge?

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tube and has a magnitude of 5.00X104 N/C?

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  1. F = εq

    as F is the force of the electric field on the proton

    ε is the magnitude of the electric field

    q is the proton charge = 1.6*10^ -19 Columbs

    So

    F = εq = 5.00*10^4 * 1.6*10^ -19 = 8*10^ -15 N

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