What is the frictional force on the 4 kg block in this case?

Question

A 4-kg block resting on a 30° incline is attached to a second block of mass m

By a cord that passes over a smooth peg. The coefficient of static friction between the block and the incline is 0.4.if m=1 kg, the system will be in static equilibrium.

Answer 1

friction force is the coefficient of static friction multiplied by normal force ... a normal force is the force vertical to any block ... so here normal force of the 4 kg block is 4 x 9.81 x cos 30 = 33.983 N

multiplied by (0.4) = 13.593 N and this is the friction force