What is the greatest common factor for the following set of numbers: 56, 252 and 168? ?

Question

Please i really need help and fast please help me.. ill give you my phone number ( if youre fine) ..!! please im desprite

Answer 1

28

2 x 28 =56

9 x 28 = 252

6 x 28 = 168

Answer 2

It's not a good idea to ever offer personal information in a public forum.

As for the question.  Factor the numbers into their prime factors first:

56 = 8 x 7

56 = (2 x 4) x 7

56 = 2 x 2 x 2 x 7

252 = 4 x 63

252 = (2 x 2) x (9 x 7)

252 = 2 x 2 x 3 x 3 x 7

168 = 4 x 42

168 = (2 x 2) x (6 x 7)

168 = 2 x 2 x 2 x 3 x 7

Now look at the final results and pull out the prime factors that repeat in *all* factorizations:

56 = 2 x 2 x 2 x 7

252 = 2 x 2 x 3 x 3 x 7

168 = 2 x 2 x 2 x 3 x 7

You have 2 x 2 that appears in each and a 7.  You can't take another 2 or any 3 because you can't take more than the minimum that appear in each.

GCF = 2 x 2 x 7 = 28

Answer:

28

Answer 3

It's 28 :) xx

Answer 4

28