Question:

What is the magnetic dipole moment?

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A magnet in the form of a cylindrical rod has a length of 50 cm and a diameter of 1 cm. It has a uniform magnetization of 5.30 x 10^3 A/m. What is the magnetic dipole moment?

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  1. Given:

    r = 0.5cm = 0.005m

    L = 50cm = 0.5m

    M = 5.3 × 10³ A/m

    Known:

    μo = 4*π × 10^7 Tm/A

    First, find the magnetic field:

    B = μo * M = ...

    Then find the magnetic dipole moment using B:

    μ = I * A = [(2*π*r*B)/μo] * [π*r²] = ...

    Plug & chug...

    [your answer should be on the order of 10^-4]

    [units for μ are J/T or A*m²]

    [unit conversion for teslas: T = N/(A*m)]

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