Question:

What is the magnitude and direction of the force between two parallel wires 45 m long and 6.0 cm apart, each?

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carring 35A in the same direction ?

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  1. F/L = µ*I1*I2/(2πD) = 4.08333333333333D-03 N/m

    F = F/L * 45 = 0.18375 N

    Since both currents are in the same direction, the force is attractive.

    See the ref.

    µ is free-space permeability = 4π*1E-7 = 1.25663706E-06 N/A^2

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