What is the magnitude and direction of the resultant force of the tree?

Question

Three people are pulling on a tree. The first person pulls with 15 N at 65 degrees; the second with 16 N at 135 degress; the third with 11 N at 195 degrees. What is the magnitude and direction of the resultant force of the tree?

Answer 1

y  = 15cos(65)+16cos(135)+11cos(195) = -15.599

x  = 15sin(65)+16sin(135)+11sin(195) = 22.06

f = sqrt(x^2+y^2) = 27.01N

alpha  = 90+tan^-1(y/x) = 90+35.26 = 125 degres

hope this lelps

Answer 2

horizontal component= 16cos 45 +15cos 25 - 11sin 15

                                     =22.1 N

Vertical component   = 16cos45+11cos15 -15cos65

                                    =15.6 N

resultant force = 27.1N, at angle 54.7degrees

Answer 3

IM MORE THAN LIKELY WRONG BUT

i came up with....

42N pulling in an angle of 25 degrees

once again like i said IM MOST LIKELY WRONG..

brain not functioning right...

mainly cuz  its 6:30 0-o