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What is the mass-action expression, Qc, for this reaction?

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NO(g) + 1/2Br2(g) <=> NOBr(g)

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  1. for this equilibrium with these moles, NO(g) + 1/2Br2(g) &lt;=&gt; NOBr(g),.... it is

    K = [NOBr]  /  [NO] [Br2]^1/2

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