What is the maximum height a stone will reach if thrown straight up with an initial speed of 10m/s?

Question

What is the maximum height a stone will reach if thrown straight up with an initial speed of 10m/s?

Answer 1

The other method (the first being delivered in the above post) is using equations of motion:

U= 10m/s

V = 0 m/s (stops no speed upwards at maximum height)

a = -9.8 m/s (squared)

now you simply plug in the information:

v(squared) = u(squared) + 2ad

0 = 100 - 19.6d

-100/-19.6 = d = 5.1 meters upwards.

Answer 2

We know that kinetic energy becomes potential energy when its velocity becomes zero.

KE = PE

½mv² = mgh

Solve for the height.

h = v² / 2g

= (10 m/s)² / (2 x 9.8 m/s²)

= 5.1 m