What is the missing number in this equation?

Question

( ) C4H10 1302---->8CO2 10H2O

Answer 1

2....boy oh boy I hated balancing equations!!! The easiest way to do this is write all of the elements out and see what you are missing.  See first which elements balance on each side and which ones don't.  Then figure out what the difference would be to make that element balance.  

On the right you have 8 carbon, 26 oxygen, and 20 hydrogen.  No take what you have on the left.  You have 26 oxygen on the left....so that balances.  You have 4 carbon and 10 hydrogen..so If you add 2 in the space you need to figure, you would then have 8 carbon and 20 hydrogen...now the whole equation is balanced

Answer 2

The basic idea is to get the same number of each element on either side of the equations.  Your balanced equation is:

2C4H10 + 13O2 = 8CO2 + 10H2O

If you go to the following web site, assuming you have the proper subscripts, it will balance your equations for you:

http://adomas.org/bceq/

Since you won't always have access to a computer to have your equations balanced for you, it's probably a good idea to learn how to do it.  The following site is excellent in teaching you a very easy way to do it:

http://misterguch.brinkster.net/eqnbalan...

Answer 3

2C4H10 + 13O2 → 8CO2 + 10H2O

Answer 4

Number of C on both right and left side should be equal.

8 C on the product (right) side ->  need 8 on the reactant (left) side, the only source of C from reactant side (right side) is C4H10 then

2 mole C4H10 to get 8 C on the right side is necessary.