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What is the molar solubility of PbBr2?? the Ksp=6.6e-6?

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What is the molar solubility of PbBr2?? the Ksp=6.6e-6?

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  1. What I did was set up a reaction table.

    .................. PbBr2(s)..... <-->...... Pb2+(aq)....+..... 2Br-(aq)

    Initial............... -................................ 0......................... 0

    Reacting......... -.............................. +x....................... +2x

    Equilibrium..... -................................ x......................... 2x

    [Pb2+] = x [Br-] = 2x

    Write out the solubility product constant.

    Ksp = [Pb2+][Br-]^2       Ksp = 6.6*10^-6

    6.6*10^-6 = (x)(2x)^2

    6.6*10^-6 = x(4x^2)

    6.6*10^-6 = 4x^3

    There is a one to one mole ratio between Pb2+ and PbBr2.

    x = [Pb2+] = [PbBr2] = .0118M

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