What is the natural log of 1?

Question

i'm guessing this a pretty simple question. i just forgot how to do it. thanks

Answer 1

zero as e^0 = 1

math kp

Answer 2

0

Answer 3

Well if you write the question as a formula and your answer is y then:

Ln(1) = y ,

then 1 = exp(y)

At this point you could say exp(0) =1 so your answer is y = 0.

Otherwise you could use the Taylor expansion for the exponential to solve for y:

1 = exp(y) = 1 + y +(y^2)/2 ....

to which the only solution is y = 0