What is the osmotic pressure of a solution made from dissolving 70.0 g of glucose, , in 500 of water at 29.0?

Question

What is the osmotic pressure of a solution made from dissolving 70.0 g of glucose,C(six)H(twelve)O(six) , in 500 ml of water at 29.0 Degrees C?

Answer 1

Moles glucose = 70.0 g / 180 g/mol = 0.389

V = 0.500 L

T = 29 + 273 =302 K

osmotic pressure = 0.389 x 0.0821 x 302/ 0.500