What is the outcome of mixing aqueous tin(II) chloride and acidified aqueous hydrogen peroxide. Why is it so?

Question

What is the outcome of mixing aqueous tin(II) chloride and acidified aqueous hydrogen peroxide. Why is it so?

Answer 1

your answer is: Sn+2 is oxidized to Sn+4

because H2O2 can pull electrons with enough force to do so:

H2O2  & 2 H+ -- 2 H2O  Eo = +1.776 volts

H2O2 takes electrons as an oxidizer with a force of 1.776 volts and all it has to over come is the much weaker forrce of 0.154 volts with which Sn+2 resists:

Sn+2  -->  Sn+4  & 2 electrons  Eo = - 0.154 volts

data form a table of reduction potentials