What is the outside area of a tank that is 214'across and 32' high trying to figure how much paint it willneed

Question

What is the outside area of a tank that is 214'across and 32' high trying to figure how much paint it willneed

Answer 1

PI Is 3.14 Times the 1/2 the diameter of 107ft. is 335.98 times the height of 32ft is= 10751.36     So if you buy enough paint to cover 10,755sq.ft you should cover it all, just don't spill any.

Answer 2

214x32=6848

that is the area. but if it is a tank, do you want to know the surface area? what is the width?

Answer 3

i would say around 40 gal,

Answer 4

are we talking about a tank with a circular cross-section and a diameter of 214'?  If so, the area of the sidewall would be (214*pi*32) = 21,500 sq. ft.  If this tank had a top, it would add another 36,000 sq ft.

For a estimate of the amount of paint you need, Benjamin Moore has direct-to-metal exterior paints that are self-priming.  They have a theoretical coverage of 380 sq ft/gallon.  For just the sidewalls, it would take about 57 gallons at that coverage.  What you will actually get will depend on several factors, but 57 gallons should be in the ballpark.

Answer 5

Ok, so assuming we have a round tank that is 32" tall and has a diameter of 214', the calculations would be as follows:

For the top and bottom, we use the Area of a Circle calculation (pi x radius x radius) 3.1416 x 107 x 107 = 35968.1784 rounded up to 35969 sq ft

For the walls, we would use the circumference of a circle calculation (diameter x pi) 214*3.1416 = 730.7244 rounded up to 731 feet. We then take the 731 feet and multiply by the height (32') and we come up with: 731 x  32 = 23392 sq ft

You will need enough paint to cover 23392 + 35969 = 69,361 sq ft if you are only painting the outside of the walls and outside of the top.