Question:

What is the pH of a buffer containing 0.45 mol of CH3COOK added to 1.00L of 2.0M CH3COOH?

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assume pKa of acetic acid is 4.75

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  1. Concentration CH3COO- = 0.45 mol / 1.00 L = 0.45

    concentration CH3COOH = 2.0 M

    pH = pKa + log [CH3COO-] / [CH3COOH] =

    = 4.75 + log 0.45 / 2.0 = 4.10

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