What is the probability of choosing a blue and then a green without replacing the blue?

Question

Ok so you hve a box that contains

4 red

3 greens

2 blue

3 black

what is the probability of choosing a blue and then a green without replacing the blue?

Answer 1

1 in 22

Answer 2

::4

::3

::2

+3

===

12



Blue = 2/12

Green = 3/11 Because the blue is not replaced

(2/12)*(3/11) = 6 /132

Simplified:

1 / 22

By the way, this must be either be in the Mathematics or Homework help section.

Answer 3

2/20 i think

Answer 4

The probability of choosing the blue is 1/6

(1 over 6) and the chance of choosing green without replacing the blue is 3/11 (3 over 11)

4+3+2+3=12; so 2 blue over 12 total choices. Which simplifies to 1/6. Same goes for the probability of choosing a green. Just add 4+3+1+3=11; 3 green over 11 total.

Answer 5

4x3x2x3=72

4x3x1x3=36

72+36=128

1 in 128 chance

Answer 6

do your homework