What is the quadratic formula for x² - 4x - 3 = 0 how to solve it?

Question

please help. i need it tonight!!!!!!!!!!!!!!!!!

Answer 1

1st value of x:

x² - 4x - 3 = 0

x² - 4x = 3

x² - 2x = 3 + (- 2²)

x² - 2x = 3 + 4

(x - 2)² = 7

x - 2 = 2.64575

x = 4.64575

2nd value of x:

x - 2 = - 2.64575

x = - 0.64575

Answer: x = 4.64575, - 0.64575; Factors: (x - 4.64575)(x + 0.64575)

Proof:

4.64575² - 4(4.64575) = 3

21.583 - 18.583 = 3

3 = 3

Proof:

- 0.64575² - 4(- 0.64575) = 3

0.417 + 2.583 = 3

3 = 3

Answer 2

x² - 4x - 3 = 0

a = 1

b = -4

c = -3

Substitute your values in the formulas below

and grab a calculator:

-b/2a + -1 * Sqr(b ^ 2 - 4 * a * c)/2a

-b/2a + Sqr(b ^ 2 - 4 * a * c)/2a

x= 2 -2.6457

x= 2 + 2.6457

x= -0.64575

x= 4.645751

remember order of operations!

Answer 3

The Quadratic Formula for

ax^2+bx+c=0 is

[-b +/- √(b^2-4ac)]/2a

so for x^2 - 4x - 3 = 0 it is

[4 +/- √(16 - 4(-3))]/2 = 2 +/- .5√28 = 2 +/- √7 so

x = 2 + √7

x = 2 - √7

Which describes the zeros of your function, which you can verify by plugging them in.

Answer 4

  set in quadratic formula

x² - 4x - 3 = 0

a =1 (1x²)

b = -4  (- 4x)

c -3

{ 4   ± Sq Root ( 16  +  12 ) }  ÃƒÂƒÃ‚·  2

(4 + sq r 24)/2

(4 - sq r 24)/2

x1  =    4.6458

x2 =    -0.64575

See link for format of the quadratic equation

Answer 5

Question Number 1 :

For this equation x^2 + 4*x + 3 = 0 , answer the following questions :

A. Find the roots using Quadratic Formula !

Answer Number 1 :

The equation x^2 + 4*x + 3 = 0 is already in a*x^2+b*x+c=0 form.

As the value is already arranged in a*x^2+b*x+c=0 form, we get the value of a = 1, b = 4, c = 3.

1A. Find the roots using Quadratic Formula !

  Use the formula,

    x1 = (-b+sqrt(b^2-4*a*c))/(2*a) and x2 = (-b-sqrt(b^2-4*a*c))/(2*a)

  As we know that a = 1, b = 4 and c = 3,

  we just need to subtitute the value of a,b and c in the abc formula.

  Which produce x1 = (-(4) + sqrt( (4)^2 - 4 * (1)*(3)))/(2*1) and x2 = (-(4) - sqrt( (4)^2 - 4 * (1)*(3)))/(2*1)

  Which make x1 = ( -4 + sqrt( 16-12))/(2) and x2 = ( -4 - sqrt( 16-12))/(2)

  Which is the same with x1 = ( -4 + sqrt( 4))/(2) and x2 = ( -4 - sqrt( 4))/(2)

  We got x1 = ( -4 + 2 )/(2) and x2 = ( -4 - 2 )/(2)

  The answers are x1 = -1 and x2 = -3