What is the rate of consumption of O2 ?

Question

2 C2H2 + 5 O2 ------> 4 CO2 + H2O

when the rate of formation is 5.91 X 10^-2?

Answer 1

Since the rates of appearance of a product and disappearance of a  reactant are related to the coefficients in the balanced chemical equation, we have to know WHAT has a rate of appearance of 5.91 x 10^-2 (units).  The units would be nice to know, too.

===== Follow up =====

See, Andrew is missing it, too.  In fact, he's missing the fact that he must know WHICH product has the given rate of appearance before he can make ANY statement about the rate of disappearance of oxygen.

Answer 2

You have to be missing something in your question, what is 5.91E-2 representing, the formation of what?  Moles CO2 per second?  If so, then the answer is the ratio of the O2 and CO2, which is 5/4.

If 5.91E-2 is a rate constant, its a different problem altogether.  Either you're missing something, or I am...

Edit:  Yes, pisgahchemist... we definitely need clarification here.

Answer 3

The equation is not correct.

You have 10 O's on the right side but only 9 on the left.4 H on the left don't match the 2 on the right side. So the equation must be:

2 C2H2 + 5 O2 -> 4CO2 + 2 H2O

Let A= C2H2 and  B=O2 and C= CO2

then -rA/2=-rB/5= rC/4

=> rB=-5/4 * rC= -1.25*5.91*10^-2 mol/s= -7.39*10¯2 mol/s

Answer 4

Learn to do ur homework urself !!