What is the rate of the reaction, if the concentration of the reactant is reduced to half?

Question

A reaction is 2nd order with respect to a reactant. What is the rate of the reaction if the concentration of reactant is reduced to half ?

Answer 1

Reaction rates:

0th - order with respect to reactant: [R]^0 1/2 gives no change

1st - order with respect to reactant: [R]^1 1/2ing gives 1/2ing

2nd - order with respect to reactant: [R]^2 1/2ing gives 1/4ing

Answer 2

rate of reaction will get halfed too as due to collision theory

Answer 3

1/4

Answer 4

you cabn check this site

http://www.science.uwaterloo.ca/~cchieh/...

Answer 5

A===>B

Rate1=k[A]²

Rate2=k[0.5A]²

=(1/4)k[A]²

So the rate is one-fourth (1/4) of what it was before the concentration of that reactant was reduced to half.

Answer 6

1/4

For 2nd order reactions, the half life depends on the initial concentration, [A]o, and the rate constant k:

hl = 1 / (k [A]o)

hl * k [A]o = 1

Since the concentration is reduced to half of its original value at the end of its first half-life, the second half-life is twice as long as the first half life. Thus, a plot of [A] vs. t easily reveal the order of the reaction by tracking its half life.

Either plot [A] vs. t or plot the appropriate linear relationship will reveal the order of the reaction. Both types are available in the simulation. Unfortunately, when we switched to the present format, the simulation cannot be implemented here.

Answer 7

0.25(actual reaction rate without change in reactant conc.)